Question

(13分) 解不等式．

Answer 1

{x|-1＜x≤1或2≤x＜3}

本試題主要是考查了分式不等式的求解，將分式不等式轉化為一元二次不等式來求解的等價轉換思想的運用。先通分合并，再將分式寫為整式，利用二次不等式的思想求解得到結論。
解：原不等式等價于≤0 ······················ 4分
≤0····························· 8分

由數軸穿根法可知原不等式解集為
{x|-1＜x≤1或2≤x＜3}··························· 13分